In the F_2 generation of a dihybrid cross,how | vedclass

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(C) In a dihybrid cross,the $F_2$ generation is produced by the selfing of $F_1$ dihybrids $(AaBb 	imes AaBb)$.According to the law of independent as

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$9$

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(C) In a dihybrid cross,the $F_2$ generation is produced by the selfing of $F_1$ dihybrids $(AaBb 	imes AaBb)$.According to the law of independent assortment,the phenotypic ratio is $9:3:3:1$.The number of genotypes can be calculated using the formula $3^n$,where $n$ is the number of gene pairs involved.For a dihybrid cross,$n = 2$.Therefore,the number of genotypes = $3^2 = 9$.The $9$ genotypes are: $AABB, AABb, AaBB, AaBb, AAbb, Aabb, aaBB, aaBb, aabb$.

In the $F_2$ generation of a dihybrid cross,how many types of genotypes are produced?

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