Albinism in humans is controlled by a recessi | vedclass

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(C) Let the normal allele be $A$ and the recessive allele for albinism be $a$. An individual with albinism must have the genotype $aa$. If $50\%$ of t

Vedclass · Accepted Answer

The father is homozygous recessive for albinism and the mother is heterozygous.

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(C) Let the normal allele be $A$ and the recessive allele for albinism be $a$. An individual with albinism must have the genotype $aa$. If $50\%$ of the children are affected $(aa)$,it implies that the cross must be between a heterozygous parent $(Aa)$ and a homozygous recessive parent $(aa)$. This is a test cross: $Aa 	imes aa ightarrow 50\% \ Aa$ (normal carrier) and $50\% \ aa$ (albino). Therefore,one parent must be heterozygous $(Aa)$ and the other must be homozygous recessive $(aa)$.

Albinism in humans is controlled by a recessive gene. If a couple has children and $50\%$ of them exhibit albinism,what does this indicate about the parents' genotypes?

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