If the diploid number in G_1 phase is 8,what | vedclass

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(B) In the $G_1$ phase,the diploid number $(2n)$ is $8$.During meiosis-$I$ (reductional division),the homologous chromosomes separate,resulting in two

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$4$ and $4$

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(B) In the $G_1$ phase,the diploid number $(2n)$ is $8$.During meiosis-$I$ (reductional division),the homologous chromosomes separate,resulting in two daughter cells,each with a haploid number of chromosomes $(n)$.Therefore,after meiosis-$I$,the number of chromosomes in each daughter cell is $n = 8/2 = 4$.Meiosis-$II$ is an equational division similar to mitosis,where the number of chromosomes remains the same as in the cells entering this phase.Thus,after meiosis-$II$,the number of chromosomes in each daughter cell remains $4$.

If the diploid number in $G_1$ phase is $8$,what should be the number of chromosomes in daughter cells after meiosis-$I$ and meiosis-$II$,respectively?

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