During the conduction of a nerve impulse alon | vedclass

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(D) $1$. At the resting state,the axonal membrane is polarized,meaning the inner side is negatively charged relative to the outer side.$2$. When a sti

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First negative,then positive,and then negative again

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(D) $1$. At the resting state,the axonal membrane is polarized,meaning the inner side is negatively charged relative to the outer side.$2$. When a stimulus is applied,the membrane becomes permeable to $Na^+$ ions,causing an influx of $Na^+$. This leads to depolarization,where the inner side becomes positively charged.$3$. Following this,the membrane becomes permeable to $K^+$ ions,which move out,leading to repolarization,where the inner side becomes negatively charged again.$4$. Thus,the sequence of charge on the inner side is negative (resting),positive (depolarized),and negative (repolarized).

During the conduction of a nerve impulse along a neuron,what is the nature of the electrical charge on the inner side of the plasma membrane?

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