Calculate the entropy change for the melting | vedclass

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Question

(A) The entropy change $\Delta S$ for a phase transition is given by $\Delta S = \frac{q_{rev}}{T} = \frac{m 	imes L_f}{T}$.Given: Mass $m = 1 \, kg

Vedclass · Accepted Answer

$1230$

Vedclass · Answer

(A) The entropy change $\Delta S$ for a phase transition is given by $\Delta S = \frac{q_{rev}}{T} = \frac{m 	imes L_f}{T}$.Given: Mass $m = 1 \, kg = 1000 \, g$,Latent heat $L_f = 80 \, cal \, g^{-1} = 80 	imes 4.2 \, J \, g^{-1} = 336 \, J \, g^{-1}$,Temperature $T = 0 \, ^\circ C = 273 \, K$.Substituting the values: $\Delta S = \frac{1000 \, g 	imes 336 \, J \, g^{-1}}{273 \, K} = \frac{336000}{273} \, J \, K^{-1} = 1230.67 \, J \, K^{-1}$.

Calculate the entropy change for the melting of $1 \, kg$ of ice at $0 \, ^\circ C$ in $SI$ units. (Latent heat of fusion of ice = $80 \, cal \, g^{-1}$) (in $.67$)

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