Given: 2Zn + O_2 rightarrow 2ZnO, Delta G^o = | vedclass

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(A) The target reaction is: $2ZnS + 3O_2 \rightarrow 2ZnO + 2SO_2$. We can obtain this by manipulating the given equations: $(1) 2Zn + O_2 \rightarrow

Vedclass · Accepted Answer

$-731$

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(A) The target reaction is: $2ZnS + 3O_2 \rightarrow 2ZnO + 2SO_2$. We can obtain this by manipulating the given equations: $(1) 2Zn + O_2 \rightarrow 2ZnO, \Delta G^o = -616 \, J$ $(2) 2ZnS \rightarrow 2Zn + S_2, \Delta G^o = +293 \, J$ (Reversing the second given equation) $(3) S_2 + 2O_2 \rightarrow 2SO_2, \Delta G^o = -408 \, J$ Adding these three equations: $(2Zn + O_2) + (2ZnS) + (S_2 + 2O_2) \rightarrow (2ZnO) + (2Zn + S_2) + (2SO_2)$ Canceling common terms ($2Zn$ and $S_2$): $2ZnS + 3O_2 \rightarrow 2ZnO + 2SO_2$ The total $\Delta G^o = (-616) + (+293) + (-408) = -731 \, J$.

Given: $2Zn + O_2 \rightarrow 2ZnO, \Delta G^o = -616 \, J$; $2Zn + S_2 \rightarrow 2ZnS, \Delta G^o = -293 \, J$; $S_2 + 2O_2 \rightarrow 2SO_2, \Delta G^o = -408 \, J$. The value of $\Delta G^o$ for the reaction $2ZnS + 3O_2 \rightarrow 2ZnO + 2SO_2$ is ....... $J$.

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