For the combustion of sucrose (C_{12}H_{22}O_ | vedclass

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(C) The combustion reaction of sucrose is: $C_{12}H_{22}O_{11}(s) + 12O_2(g) \rightarrow 12CO_2(g) + 11H_2O(l)$.Calculate the change in the number of

Vedclass · Accepted Answer

$\Delta H = \Delta U$

Vedclass · Answer

(C) The combustion reaction of sucrose is: $C_{12}H_{22}O_{11}(s) + 12O_2(g) ightarrow 12CO_2(g) + 11H_2O(l)$.Calculate the change in the number of moles of gaseous species,$\Delta n_g = n_p(g) - n_r(g)$.Here,$n_p(g) = 12$ (from $12CO_2$) and $n_r(g) = 12$ (from $12O_2$).Therefore,$\Delta n_g = 12 - 12 = 0$.The relationship between enthalpy change and internal energy change is given by $\Delta H = \Delta U + \Delta n_g RT$.Since $\Delta n_g = 0$,we get $\Delta H = \Delta U + 0 	imes RT$,which implies $\Delta H = \Delta U$.

For the combustion of sucrose $(C_{12}H_{22}O_{11})$ at $250\,^oC$,which of the following is true?

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