In the reaction $4NH_{3(g)} + 5O_{2(g)} \rightarrow 4NO_{(g)} + 6H_2O_{(g)}$,when $1 \ mol$ of ammonia and $1 \ mol$ of $O_2$ react to completion:

  • A
    $1.0 \ mol$ of $H_2O$ is produced
  • B
    $1.0 \ mol$ of $NO$ is produced
  • C
    All the oxygen is consumed
  • D
    No oxygen is consumed

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$NH_3$ is produced according to the following reaction: $N_{2(g)} + 3H_{2(g)} \rightarrow 2NH_{3(g)}$. In an experiment,$0.25 \ mol$ of $NH_3$ is formed when $0.5 \ mol$ of $N_2$ is reacted with $0.5 \ mol$ of $H_2$. What is the percentage yield (in $\%$)?

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