How many moles of $NaOH$ are present in $27 \, mL$ of $0.15 \, M \, NaOH$?

  • A
    $2.27 \times 10^4$
  • B
    $2.67 \times 10^{-4}$
  • C
    $4.05 \times 10^{-3}$
  • D
    $3.34 \times 10^2$

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$SO_{2}Cl_{2}$ on reaction with excess of water results in an acidic mixture: $SO_{2}Cl_{2} + 2H_{2}O \rightarrow H_{2}SO_{4} + 2HCl$. If $16 \, moles$ of $NaOH$ is required for the complete neutralization of the resultant acidic mixture,calculate the number of moles of $SO_{2}Cl_{2}$ used.

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