How many grams of oxygen are present in 32.2 | vedclass

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(D) The molar mass of $Na_2SO_4 \cdot 10H_2O$ is calculated as:$M = 2(23) + 32 + 4(16) + 10 	imes (2 	imes 1 + 16) = 46 + 32 + 64 + 180 = 322 \ g/mo

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$22.4$

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(D) The molar mass of $Na_2SO_4 \cdot 10H_2O$ is calculated as:$M = 2(23) + 32 + 4(16) + 10 	imes (2 	imes 1 + 16) = 46 + 32 + 64 + 180 = 322 \ g/mol$.In one mole of $Na_2SO_4 \cdot 10H_2O$,there are $4$ oxygen atoms in $Na_2SO_4$ and $10$ oxygen atoms in $10H_2O$,totaling $14$ oxygen atoms.Mass of oxygen in $1 \ mol$ $(322 \ g)$ of $Na_2SO_4 \cdot 10H_2O = 14 	imes 16 \ g = 224 \ g$.Therefore,the mass of oxygen in $32.2 \ g$ of $Na_2SO_4 \cdot 10H_2O = (224 / 322) 	imes 32.2 = 22.4 \ g$.

How many grams of oxygen are present in $32.2 \ g$ of $Na_2SO_4 \cdot 10H_2O$ (in $g$)?

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