In two compounds,each containing tin (Sn) and | vedclass

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(C) For compound $A$,the ratio of $Sn$ to $O$ is $78.77 / 21.23 \approx 3.71$. For compound $B$,the ratio of $Sn$ to $O$ is $88.12 / 11.88 \approx 7.4

Vedclass · Accepted Answer

Law of Multiple Proportions

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(C) For compound $A$,the ratio of $Sn$ to $O$ is $78.77 / 21.23 \approx 3.71$. For compound $B$,the ratio of $Sn$ to $O$ is $88.12 / 11.88 \approx 7.42$. Now,consider the ratio of the masses of $Sn$ that combine with a fixed mass of $O$ in both compounds: Ratio $= 3.71 / 7.42 = 1 / 2$. Since the ratio of the masses of $Sn$ is a simple whole number ratio $(1:2)$,this illustrates the Law of Multiple Proportions.

Compound	$\% Sn$	$\% O$
$A$	$78.77$	$21.23$
$B$	$88.12$	$11.88$

In two compounds,each containing tin $(Sn)$ and oxygen,the composition is as follows. Which law of chemical combination can be illustrated by this data?

Compound $\% Sn$ $\% O$

$A$ $78.77$ $21.23$

$B$ $88.12$ $11.88$

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In two compounds,each containing tin $(Sn)$ and oxygen,the composition is as follows. Which law of chemical combination can be illustrated by this data? Compound $\% Sn$ $\% O$ $A$ $78.77$ $21.23$ $B$ $88.12$ $11.88$