If the price of 1 kg of common salt is 7 rup | vedclass

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Question

(C) Molar mass of common salt $(NaCl)$ = $58.5 \ g/mol$. Molar mass of sugar $(C_{12}H_{22}O_{11})$ = $342 \ g/mol$.Number of moles in $1 \ kg$ $(1000

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The price of sugar is more than the price of salt.

Vedclass · Answer

(C) Molar mass of common salt $(NaCl)$ = $58.5 \ g/mol$. Molar mass of sugar $(C_{12}H_{22}O_{11})$ = $342 \ g/mol$.Number of moles in $1 \ kg$ $(1000 \ g)$ of salt = $\frac{1000}{58.5} \approx 17.09 \ mol$.Number of moles in $1 \ kg$ $(1000 \ g)$ of sugar = $\frac{1000}{342} \approx 2.92 \ mol$.Cost of $1 \ mole$ of salt = $\frac{7 	imes 58.5}{1000} = 0.4095 \ rupees$.Cost of $1 \ mole$ of sugar = $\frac{14 	imes 342}{1000} = 4.788 \ rupees$.Comparing the two,the cost of $1 \ mole$ of sugar is significantly higher than the cost of $1 \ mole$ of salt.

If the price of $1 \ kg$ of common salt is $7$ rupees and the price of $1 \ kg$ of sugar is $14$ rupees,then what is the cost of $1 \ mole$ of salt and sugar?

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