(C) $22.4 \ L$ of oxygen gas corresponds to $1 \ mol$ of molecules at $STP$.Number of mole molecules in $56 \ L = \frac{56}{22.4} = 2.5 \ mol$ of mole

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(C) $22.4 \ L$ of oxygen gas corresponds to $1 \ mol$ of molecules at $STP$.Number of mole molecules in $56 \ L = \frac{56}{22.4} = 2.5 \ mol$ of molecules.We know that,$\text{mole atoms} = \text{atomicity} \times \text{mole molecules}$.For oxygen $(O_2)$,atomicity is $2$.Therefore,$\text{mole atoms} = 2 \times 2.5 = 5 \ mol$ of atoms.

Class 11 Chemistry Some Basic Concepts of Chemistry The mole concept

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The number of mole atoms and mole molecules in $56 \ L$ of oxygen gas at $STP$ are respectively:

A
$5 \ mol, 0.5 \ mol$
B
$10 \ mol, 1 \ mol$
C
$5 \ mol, 2.5 \ mol$
D
$5 \ mol, 1.5 \ mol$

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Some Basic Concepts of Chemistry

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The mole concept

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The number of mole atoms and mole molecules in $56 \ L$ of oxygen gas at $STP$ are respectively:

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