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Question

(B) The equivalent weight of an element is defined as the mass of the element that combines with $8 \, g$ of oxygen.Given that $4 \, g$ of $Cu$ produc

Vedclass · Accepted Answer

$32$

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(B) The equivalent weight of an element is defined as the mass of the element that combines with $8 \, g$ of oxygen.Given that $4 \, g$ of $Cu$ produces $5 \, g$ of copper oxide.Therefore,$4 \, g$ of $Cu$ combines with $(5 - 4) = 1 \, g$ of oxygen.Using the unitary method:$1 \, g$ of oxygen combines with $4 \, g$ of $Cu$.So,$8 \, g$ of oxygen will combine with $\frac{4 	imes 8}{1} = 32 \, g$ of $Cu$.The equivalent weight of copper is $32 \, g \, eq^{-1}$.

$4 \, g$ of copper is dissolved in concentrated $HNO_3$. Upon strong heating of the resulting copper nitrate solution,$5 \, g$ of its oxide is obtained. The equivalent weight of copper is ...... .

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