How much MgO is produced from 1.2 g of Mg (a | vedclass

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(C) The balanced chemical equation for the reaction is: $2Mg + O_2 	o 2MgO$. From the stoichiometry,$2 \ mol$ of $Mg$ produces $2 \ mol$ of $MgO$. Th

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$2 \ g$

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(C) The balanced chemical equation for the reaction is: $2Mg + O_2 	o 2MgO$. From the stoichiometry,$2 \ mol$ of $Mg$ produces $2 \ mol$ of $MgO$. Therefore,$1 \ mol$ of $Mg$ produces $1 \ mol$ of $MgO$. Number of moles of $Mg = \frac{1.2 \ g}{24 \ g/mol} = 0.05 \ mol$. Since $1 \ mol$ of $Mg$ gives $1 \ mol$ of $MgO$,$0.05 \ mol$ of $Mg$ will produce $0.05 \ mol$ of $MgO$. Molar mass of $MgO = 24 + 16 = 40 \ g/mol$. Mass of $MgO = 0.05 \ mol 	imes 40 \ g/mol = 2 \ g$.

How much $MgO$ is produced from $1.2 \ g$ of $Mg$ (atomic mass $= 24$)?

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