The volume of a gas in a discharge tube at ST | vedclass

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Question

(C) At $STP$,$22400 \ mL$ of gas contains $6.022 	imes 10^{23}$ molecules (Avogadro's number,$N_A$).Number of molecules $= \frac{	ext{Given volume}}

Vedclass · Accepted Answer

$3.01 	imes 10^{12}$

Vedclass · Answer

(C) At $STP$,$22400 \ mL$ of gas contains $6.022 	imes 10^{23}$ molecules (Avogadro's number,$N_A$).Number of molecules $= \frac{	ext{Given volume}}{	ext{Molar volume at } STP} 	imes N_A$Number of molecules $= \frac{1.12 	imes 10^{-7} \ mL}{22400 \ mL/mol} 	imes 6.022 	imes 10^{23} \ mol^{-1}$Number of molecules $= \frac{1.12 	imes 10^{-7}}{2.24 	imes 10^4} 	imes 6.022 	imes 10^{23}$Number of molecules $= 0.5 	imes 10^{-11} 	imes 6.022 	imes 10^{23}$Number of molecules $= 3.011 	imes 10^{12}$

The volume of a gas in a discharge tube at $STP$ is $1.12 \times 10^{-7} \ mL$. What is the number of molecules of the gas in the tube?

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