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(A) Given: Solution $P = 8 \, N$ $H_2SO_4$ (Volume = $1 \, L$),Solution $Q = 8 \, N$ $HNO_3$ (Volume = $1 \, L$).
$(1)$ For $P$: $M = N / n$-factor $

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(A) Given: Solution $P = 8 \, N$ $H_2SO_4$ (Volume = $1 \, L$),Solution $Q = 8 \, N$ $HNO_3$ (Volume = $1 \, L$).
$(1)$ For $P$: $M = N / n$-factor $= 8 / 2 = 4 \, M$. Moles $= M 	imes V = 4 	imes 1 = 4 \, 	ext{mol}$.
For $Q$: $M = N / n$-factor $= 8 / 1 = 8 \, M$. Moles $= M 	imes V = 8 	imes 1 = 8 \, 	ext{mol}$.
Since $4 
eq 8$,statement $(1)$ is False $(F)$.
$(2)$ Gram-equivalents $= N 	imes V$. For $P = 8 	imes 1 = 8$. For $Q = 8 	imes 1 = 8$. Since $8 = 8$,statement $(2)$ is True $(T)$.
$(3)$ Mole fraction of solvent depends on the number of moles of solute. Since moles of solute are different $(4 
eq 8)$,the mole fraction of solvent will be different. Statement $(3)$ is False $(F)$.
$(4)$ For $P$: $[H^+] = N = 8 \, M$. For $Q$: $[H^+] = N = 8 \, M$. Since $8 = 8$,statement $(4)$ is True $(T)$.
Therefore,the sequence is $F, T, F, T$.

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