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(A) The density of pure water is approximately $1 \ g/mL$. For $1 \ L$ $(1000 \ mL)$ of water,the mass is $1000 \ g$. The molar mass of water $(H_2O)$

Vedclass · Accepted Answer

$55.6$

Vedclass · Answer

(A) The density of pure water is approximately $1 \ g/mL$. For $1 \ L$ $(1000 \ mL)$ of water,the mass is $1000 \ g$. The molar mass of water $(H_2O)$ is $18 \ g/mol$. Number of moles $(n)$ = $\frac{	ext{mass}}{	ext{molar mass}} = \frac{1000 \ g}{18 \ g/mol} \approx 55.56 \ mol$. Molarity $(M)$ = $\frac{	ext{moles of solute}}{	ext{volume of solution in liters}} = \frac{55.56 \ mol}{1 \ L} = 55.56 \ M \approx 55.6 \ M$.

The molarity of pure water is $......$

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