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(A) According to Avogadro's Law,at the same temperature and pressure,equal volumes of gases contain an equal number of moles. Since the volume is the

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$C_3H_8$

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(A) According to Avogadro's Law,at the same temperature and pressure,equal volumes of gases contain an equal number of moles. Since the volume is the same $(1 \ L)$,the weight of the gas is directly proportional to its molar mass. Given that the weight of the hydrocarbon is greater than the weight of $CO_2$,the molar mass of the hydrocarbon must be greater than the molar mass of $CO_2$. Molar mass of $CO_2 = 12 + (2 	imes 16) = 44 \ g/mol$. Now,calculate the molar masses of the options: $A) C_3H_8 = (3 	imes 12) + (8 	imes 1) = 44 \ g/mol$ $B) C_2H_6 = (2 	imes 12) + (6 	imes 1) = 30 \ g/mol$ $C) C_2H_4 = (2 	imes 12) + (4 	imes 1) = 28 \ g/mol$ $D) C_3H_6 = (3 	imes 12) + (6 	imes 1) = 42 \ g/mol$ Since the question implies the weight is greater than $CO_2$ $(44 \ g/mol)$,there appears to be a discrepancy in the provided options as none exceed $44 \ g/mol$. However,if the question meant 'equal to or greater',$C_3H_8$ is the closest match.

The weight of $1 \ L$ of a hydrocarbon is more than that of $1 \ L$ of $CO_2$ at the same temperature and pressure. What is the molecular formula of the hydrocarbon?

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