What is the number of water molecules present | vedclass

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(D) The density of water is $1 \ g/mL$,so $1 \ mL$ of water has a mass of $1 \ g$.The molar mass of water $(H_2O)$ is $18 \ g/mol$.The number of moles

Vedclass · Accepted Answer

$3.34 	imes 10^{22}$

Vedclass · Answer

(D) The density of water is $1 \ g/mL$,so $1 \ mL$ of water has a mass of $1 \ g$.The molar mass of water $(H_2O)$ is $18 \ g/mol$.The number of moles in $1 \ g$ of water is $n = \frac{1 \ g}{18 \ g/mol} = 0.0556 \ mol$.The number of molecules is calculated by multiplying the number of moles by Avogadro's number $(N_A = 6.022 	imes 10^{23} \ mol^{-1})$:Number of molecules $= 0.0556 \ mol 	imes 6.022 	imes 10^{23} \ mol^{-1} \approx 3.34 	imes 10^{22}$ molecules.

What is the number of water molecules present in $1 \ mL$ of water?

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