The number of atoms present in $0.1 \ mol$ of a triatomic gas is: $(N_A = 6.022 \times 10^{23} \ mol^{-1})$
- A$1.800 \times 10^{22}$
- B$6.026 \times 10^{22}$
- C$1.806 \times 10^{23}$
- D$3.600 \times 10^{23}$
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Column-$A$ Column-$B$ $1$. $55.55 \text{ mol}$ $(P)$ $6.022 \times 10^{23}$ molecules of sucrose $2$. $2 \text{ mol}$ $(Q)$ $1.8 \text{ g}$ of $H_2O$ $3$. $0.1 \text{ mol}$ $(R)$ $126 \text{ g}$ of $HNO_3$ $4$. $0.01 \text{ mol}$ $(S)$ $1 \text{ L}$ of pure water
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| $1$. $55.55 \text{ mol}$ | $(P)$ $6.022 \times 10^{23}$ molecules of sucrose |
| $2$. $2 \text{ mol}$ | $(Q)$ $1.8 \text{ g}$ of $H_2O$ |
| $3$. $0.1 \text{ mol}$ | $(R)$ $126 \text{ g}$ of $HNO_3$ |
| $4$. $0.01 \text{ mol}$ | $(S)$ $1 \text{ L}$ of pure water |
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