Carbon and oxygen form two known compounds. O | vedclass

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(B) In the first compound,$C = 42.9\%$ and $O = 57.1\%$. Ratio of $C:O = \frac{42.9}{57.1} = 0.751:1$. In the second compound,$C = 27.3\%$ and $O = 72

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Multiple Proportions

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(B) In the first compound,$C = 42.9\%$ and $O = 57.1\%$. Ratio of $C:O = \frac{42.9}{57.1} = 0.751:1$. In the second compound,$C = 27.3\%$ and $O = 72.7\%$. Ratio of $C:O = \frac{27.3}{72.7} = 0.376:1$. Comparing the ratio of $C$ for a fixed amount of $O$: Ratio $= 0.751 : 0.376 = 2 : 1$. Since the ratio is a simple whole number,this illustrates the Law of Multiple Proportions.

Carbon and oxygen form two known compounds. One compound contains $42.9\%$ carbon,while the other contains $27.3\%$ carbon. This illustrates the law of:

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