The number of molecules present in 1 liter of | vedclass

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(C) Density of water is $1 \ g/mL$,which means the mass of $1 \ mL$ of water is $1 \ g$. Thus,the mass of $1000 \ mL$ $(1 \ liter)$ of water is $1000

Vedclass · Accepted Answer

$55.5$

Vedclass · Answer

(C) Density of water is $1 \ g/mL$,which means the mass of $1 \ mL$ of water is $1 \ g$. Thus,the mass of $1000 \ mL$ $(1 \ liter)$ of water is $1000 \ g$. Molar mass of water $(H_2O)$ = $(2 	imes 1) + 16 = 18 \ g/mol$. Number of moles of water = $\frac{	ext{mass}}{	ext{molar mass}} = \frac{1000 \ g}{18 \ g/mol} = 55.55 \ mol$. Since $1 \ mol$ contains $N_A$ molecules,the number of molecules in $55.55 \ mol$ is $55.55 \ N_A$.

The number of molecules present in $1$ liter of water is: (Density of water = $1 \ g/mL$) (in $N_A$)

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