The molar mass of CO_2 is 44 g/mol. Given th | vedclass

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(B) The molar mass of $CO_2$ is $44 \ g/mol$,which means $6.022 	imes 10^{23}$ molecules of $CO_2$ weigh $44 \ g$.To find the mass of one molecule,we

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$7.31$

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(B) The molar mass of $CO_2$ is $44 \ g/mol$,which means $6.022 	imes 10^{23}$ molecules of $CO_2$ weigh $44 \ g$.To find the mass of one molecule,we divide the molar mass by the Avogadro constant:$	ext{Mass of one molecule} = \frac{44 \ g/mol}{6.022 	imes 10^{23} \ mol^{-1}}$$	ext{Mass of one molecule} \approx 7.3065 	imes 10^{-23} \ g$Rounding to two decimal places,we get $7.31 	imes 10^{-23} \ g$.

The molar mass of $CO_2$ is $44 \ g/mol$. Given that the Avogadro constant is $6.022 \times 10^{23} \ mol^{-1}$,the mass of one molecule of $CO_2$ is ..... $\times 10^{-23} \ g$.

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