A thin layer of cobalt is deposited on a plat | vedclass

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Question

(A) Area of the plate $= 0.5 \ m^2 = 0.5 	imes 10^4 \ cm^2$. Thickness of the layer $= 0.005 \ cm$. Volume of deposited cobalt $= 0.5 	imes 10^4 \ c

Vedclass · Accepted Answer

$2.27 	imes 10^{24}$

Vedclass · Answer

(A) Area of the plate $= 0.5 \ m^2 = 0.5 	imes 10^4 \ cm^2$. Thickness of the layer $= 0.005 \ cm$. Volume of deposited cobalt $= 0.5 	imes 10^4 \ cm^2 	imes 0.005 \ cm = 25 \ cm^3$. Mass of deposited cobalt $= 	ext{Volume} 	imes 	ext{Density} = 25 \ cm^3 	imes 8.9 \ g \ cm^{-3} = 222.5 \ g$. Atomic mass of cobalt $= 59 \ g \ mol^{-1}$. Number of atoms $= (	ext{Mass} / 	ext{Atomic mass}) 	imes N_A$. Number of atoms $= (222.5 / 59) 	imes 6.022 	imes 10^{23} \approx 2.27 	imes 10^{24} 	ext{ atoms}$.

$A$ thin layer of cobalt is deposited on a plate with a total area of $0.5 \ m^2$ and a thickness of $0.005 \ cm$. How many cobalt atoms are deposited on the plate? (Density of cobalt $= 8.9 \ g \ cm^{-3}$,Atomic mass of $Co = 59 \ g \ mol^{-1}$)

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