What is the weight of 1 times 10^{22} molecul | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The molar mass of $CuSO_4 \cdot 5H_2O$ is calculated as: $63.5 + 32 + (4 	imes 16) + 5 	imes (2 + 16) = 63.5 + 32 + 64 + 90 = 249.5 	ext{ g/mol

Vedclass · Accepted Answer

$4.143$

Vedclass · Answer

(B) The molar mass of $CuSO_4 \cdot 5H_2O$ is calculated as: $63.5 + 32 + (4 	imes 16) + 5 	imes (2 + 16) = 63.5 + 32 + 64 + 90 = 249.5 	ext{ g/mol}$.We know that $6.022 	imes 10^{23}$ molecules of $CuSO_4 \cdot 5H_2O$ weigh $249.5 	ext{ g}$.Therefore,the weight of $1 	imes 10^{22}$ molecules is given by:$	ext{Weight} = \frac{249.5 	ext{ g}}{6.022 	imes 10^{23} 	ext{ molecules}} 	imes 1 	imes 10^{22} 	ext{ molecules}$.$	ext{Weight} = \frac{249.5}{6.022} 	imes 10^{-1} 	ext{ g} \approx 41.43 	imes 0.1 	ext{ g} = 4.143 	ext{ g}$.

What is the weight of $1 \times 10^{22}$ molecules of $CuSO_4 \cdot 5H_2O$ in grams?

Similar Questions

How many $H$ atoms are present in $0.046 \ g$ of ethanol $(C_2H_5OH)$?

How many molecules are present in one gram of hydrogen? (Value $\times 10^{23}$)

The weight of $112 \ cm^3$ of $CH_4$ gas at $STP$ is ...... $g$.

The mass of $112 \ cm^3$ of $CH_4$ gas at $STP$ is ............. $g$.

From $44 \ mg$ of $CO_2$,$2 \times 10^{20}$ molecules of $CO_2$ are removed. The number of molecules of $CO_2$ left are (Given $N_A = 6 \times 10^{23}$):-

Vedclass Test Series

Exam Paper Generator

Online Exam Module