According to the reaction $6CO_2 + 6H_2O \rightarrow C_6H_{12}O_6 + 6O_2$,how many molecules of $CO_2$ are required to obtain $1.8 \ g$ of glucose? (Molar mass of $C_6H_{12}O_6 = 180 \ g \ mol^{-1}$) $(C = 12, H = 1, O = 16)$

  • A
    $0.06 \times 6.022 \times 10^{23}$
  • B
    $0.6 \times 6.022 \times 10^{23}$
  • C
    $60 \times 6.022 \times 10^{23}$
  • D
    $6 \times 6.022 \times 10^{23}$

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