At STP,32 g of O_2 contains 6.022 times 10^{ | vedclass

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(A) The molar mass of $O_2$ is $32 \ g/mol$. Thus,$32 \ g$ of $O_2$ corresponds to $1 \ mol$ of $O_2$ molecules,which equals $6.022 	imes 10^{23}$ mo

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$6.022 	imes 10^{23}$

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(A) The molar mass of $O_2$ is $32 \ g/mol$. Thus,$32 \ g$ of $O_2$ corresponds to $1 \ mol$ of $O_2$ molecules,which equals $6.022 	imes 10^{23}$ molecules.Similarly,the atomic mass of sulfur $(S)$ is $32 \ g/mol$. Therefore,$32 \ g$ of sulfur corresponds to $1 \ mol$ of sulfur atoms.Since $1 \ mol$ of any substance contains $6.022 	imes 10^{23}$ particles,$32 \ g$ of sulfur contains $6.022 	imes 10^{23}$ atoms.

At $STP$,$32 \ g$ of $O_2$ contains $6.022 \times 10^{23}$ molecules. How many atoms does $32 \ g$ of sulfur $(S)$ contain under the same conditions?

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