If 19.7 kg of gold is confiscated from a thi | vedclass

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(C) The molar mass of $Au$ is $197 \ g/mol$,which contains $6.022 	imes 10^{23}$ atoms.Given mass of gold = $19.7 \ kg = 19700 \ g$.Number of moles =

Vedclass · Accepted Answer

$6.022 	imes 10^{25}$

Vedclass · Answer

(C) The molar mass of $Au$ is $197 \ g/mol$,which contains $6.022 	imes 10^{23}$ atoms.Given mass of gold = $19.7 \ kg = 19700 \ g$.Number of moles = $\frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{19700 \ g}{197 \ g/mol} = 100 \ mol$.Number of atoms = $	ext{Number of moles} 	imes N_A = 100 	imes 6.022 	imes 10^{23} = 6.022 	imes 10^{25}$ atoms.

If $19.7 \ kg$ of gold is confiscated from a thief,how many atoms of gold were confiscated from him? $(Au = 197 \ g/mol)$

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