If a compound contains $C = 18.5\%$,$H = 1.55\%$,$Cl = 55.04\%$,and $O = 24.81\%$,then its empirical formula is .....
- A$CHClO$
- B$CH_2ClO$
- C$C_2H_2OCl$
- D$ClCH_2O$
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