An organic compound on analysis gives the following composition: $C = 54.5\%, O = 36.4\%, H = 9.1\%$. The empirical formula of the compound is ..

  • A
    $C_2H_4O$
  • B
    $CH_3O$
  • C
    $C_3H_6O$
  • D
    $C_4H_8O$

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$A$ welding fuel gas contains carbon and hydrogen only. Burning a small sample of it in oxygen gives $3.38 \, g$ of carbon dioxide,$0.690 \, g$ of water,and no other products. $A$ volume of $10.0 \, L$ (measured at $STP$) of this welding gas is found to weigh $11.6 \, g$. Calculate:
$(i)$ empirical formula,
$(ii)$ molar mass of the gas,and
$(iii)$ molecular formula.

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An organic compound has an empirical formula of $CH_2O$ and a molecular mass of $90$. What is its molecular formula? $(C = 12, H = 1, O = 16)$

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