If 0.0833 mol of a carbohydrate contains 1 | vedclass

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(D) Given that $0.0833 \ mol$ of carbohydrate contains $1 \ g$ of hydrogen. Therefore,$1 \ mol$ of carbohydrate contains $\frac{1}{0.0833} \approx 12

Vedclass · Accepted Answer

$C_6H_{12}O_6$

Vedclass · Answer

(D) Given that $0.0833 \ mol$ of carbohydrate contains $1 \ g$ of hydrogen. Therefore,$1 \ mol$ of carbohydrate contains $\frac{1}{0.0833} \approx 12 \ g$ of hydrogen. The empirical formula is $CH_2O$. The mass of hydrogen in one empirical unit is $2 	imes 1.008 \approx 2 \ g$. To find the value of $n$ (where molecular formula = $n 	imes$ empirical formula),we divide the total mass of hydrogen in $1 \ mol$ by the mass of hydrogen in the empirical unit: $n = \frac{12 \ g}{2 \ g} = 6$. Thus,the molecular formula is $(CH_2O)_6 = C_6H_{12}O_6$.

If $0.0833 \ mol$ of a carbohydrate contains $1 \ g$ of hydrogen and its empirical formula is $CH_2O$,determine its molecular formula.

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