When 10 , mL of 10 , M , H_2SO_4 solution is | vedclass

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Question

(A) The reaction between $H_2SO_4$ and $NaOH$ is: $H_2SO_4 + 2NaOH ightarrow Na_2SO_4 + 2H_2O$. Millimoles of $H_2SO_4 = M 	imes V(mL) = 10 \, M

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Acidic

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(A) The reaction between $H_2SO_4$ and $NaOH$ is: $H_2SO_4 + 2NaOH ightarrow Na_2SO_4 + 2H_2O$. Millimoles of $H_2SO_4 = M 	imes V(mL) = 10 \, M 	imes 10 \, mL = 100 \, mmol$. Since $1 \, mol$ of $H_2SO_4$ reacts with $2 \, mol$ of $NaOH$,$100 \, mmol$ of $H_2SO_4$ requires $200 \, mmol$ of $NaOH$. Millimoles of $NaOH$ provided = $M 	imes V(mL) = 1 \, M 	imes 100 \, mL = 100 \, mmol$. Since the amount of $NaOH$ $(100 \, mmol)$ is less than the required amount $(200 \, mmol)$,$H_2SO_4$ is in excess. Therefore,the resulting solution will be acidic.

When $10 \, mL$ of $10 \, M \, H_2SO_4$ solution is mixed with $100 \, mL$ of $1 \, M \, NaOH$ solution,the resulting solution will be .......

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