The rate of diffusion of a gas is ..... times | vedclass

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(A) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of its molecular weight $(M)$: $r_

Vedclass · Accepted Answer

$1/7$

Vedclass · Answer

(A) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of its molecular weight $(M)$: $r_1 / r_2 = \sqrt{M_2 / M_1}$.Given: Molecular weight of gas $(M_1)$ = $98$,Molecular weight of hydrogen $(M_2)$ = $2$.Substituting the values: $r_{gas} / r_{H_2} = \sqrt{2 / 98} = \sqrt{1 / 49} = 1/7$.Therefore,the rate of diffusion of the gas is $1/7$ times that of hydrogen.

The rate of diffusion of a gas is ..... times that of hydrogen. (Molecular weight = $98$)

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