If N_2,O_2,H_2,and He are filled in four sepa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ of a gas is inversely proportional to the square root of its molar mass $(M)$:

Vedclass · Accepted Answer

$H_2$

Vedclass · Answer

(C) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ of a gas is inversely proportional to the square root of its molar mass $(M)$: $r \propto \frac{1}{\sqrt{M}}$.Comparing the molar masses: $M(H_2) = 2 \ g/mol$,$M(He) = 4 \ g/mol$,$M(N_2) = 28 \ g/mol$,and $M(O_2) = 32 \ g/mol$.Since $H_2$ has the lowest molar mass,it will have the highest rate of diffusion.Therefore,$H_2$ will leak out first.

If $N_2$,$O_2$,$H_2$,and $He$ are filled in four separate car tubes at the same pressure,which one will leak out first?

Similar Questions

According to the kinetic molecular theory of gases,which of the following is true?

How can the internal energy and pressure of a gas per unit volume be represented?

$A$ football bladder contains an equimolar mixture of $H_2$ and $O_2$. What is the ratio of the rate of diffusion of $H_2$ to $O_2$?

Assertion $(A)$ At $300 \ K$, kinetic energy of $16 \ g$ of methane is equal to the kinetic energy of $32 \ g$ of oxygen.
Reason $(R)$ At constant temperature, kinetic energy of one mole of all gases is equal.

At $STP$,$0.5 \ mol$ of $H_2$ gas and $1 \ mol$ of $He$ gas:

Vedclass Test Series

Exam Paper Generator

Online Exam Module