The kinetic energy of $1 \ mol$ of an ideal gas is given by:
- A$\frac{3}{2} RT$
- B$\frac{3}{2} KT$
- C$\frac{RT}{2}$
- D$\frac{2R}{3}$
Explore More
Similar Questions
Assertion $(A)$ At $300 \ K$, kinetic energy of $16 \ g$ of methane is equal to the kinetic energy of $32 \ g$ of oxygen.
Reason $(R)$ At constant temperature, kinetic energy of one mole of all gases is equal.
Reason $(R)$ At constant temperature, kinetic energy of one mole of all gases is equal.
According to the Kinetic Molecular Theory of Gases,which of the following statements is correct?
Easy
View SolutionWhy do gases exert pressure?
Medium
View SolutionKinetic energy of molecules is highest in
Easy
View SolutionAt $298 \, K$,assuming ideal behaviour,the average kinetic energy of a deuterium molecule is
MediumKVPY 2011
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo