If equal amounts of methane and oxygen are mi | vedclass

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(B) According to Dalton's Law of Partial Pressures,the partial pressure of a gas in a mixture is equal to its mole fraction multiplied by the total pr

Vedclass · Accepted Answer

$1/2$

Vedclass · Answer

(B) According to Dalton's Law of Partial Pressures,the partial pressure of a gas in a mixture is equal to its mole fraction multiplied by the total pressure. Since equal amounts (moles) of $CH_4$ and $O_2$ are mixed,let the number of moles of each be $n$. The total number of moles is $n + n = 2n$. The mole fraction of $O_2$ is $\frac{n}{2n} = 1/2$. Therefore,the fraction of total pressure exerted by oxygen is $1/2$.

If equal amounts of methane and oxygen are mixed in an empty container at $25 \, ^oC$,what is the fraction of total pressure exerted by oxygen?

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