The ratio of the root mean square velocity of | vedclass

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(C) The root mean square velocity $(u_{rms})$ is given by the formula: $u_{rms} = \sqrt{\frac{3RT}{M}}$For $H_2$ at $50 \ K$: $u_{rms(H_2)} = \sqrt{\f

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$1$

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(C) The root mean square velocity $(u_{rms})$ is given by the formula: $u_{rms} = \sqrt{\frac{3RT}{M}}$For $H_2$ at $50 \ K$: $u_{rms(H_2)} = \sqrt{\frac{3R 	imes 50}{2}}$For $O_2$ at $800 \ K$: $u_{rms(O_2)} = \sqrt{\frac{3R 	imes 800}{32}}$The ratio is: $\frac{u_{rms(H_2)}}{u_{rms(O_2)}} = \sqrt{\frac{3R 	imes 50}{2} 	imes \frac{32}{3R 	imes 800}}$$= \sqrt{\frac{50}{2} 	imes \frac{32}{800}} = \sqrt{25 	imes 0.04} = \sqrt{1} = 1$

The ratio of the root mean square velocity of $H_2$ at $50 \ K$ to that of $O_2$ at $800 \ K$ is .......

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