In an $NaCl$ crystal,how many $Cl^{-}$ ions surround each $Na^{+}$ ion?

What is the number of atoms per unit cell in a body-centered cubic $(BCC)$ unit cell?

The ionic radii of $A^{+}$ and $B^{-}$ ions are $0.98 \times 10^{-10} \ m$ and $1.81 \times 10^{-10} \ m$. The coordination number of each ion in $AB$ is.......

The number of nearest neighbours and next nearest neighbours of an $Na^{+}$ ion in a crystal of $NaCl$ are respectively

The number of unit cells present in $39 \ g$ of potassium if it crystallizes as a body-centered cubic $(BCC)$ structure is ($N = \text{Avogadro number}$, $\text{At. wt. of potassium} = 39$).

An element occurring in the $bcc$ structure has $12.08 \times 10^{23}$ unit cells. The total number of atoms of the element in these cells will be: