The average kinetic energy per molecule of an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The average kinetic energy per molecule of an ideal gas is given by the formula $KE_{avg} = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann consta

Vedclass · Accepted Answer

$6.17 	imes 10^{-21} \, J$

Vedclass · Answer

(B) The average kinetic energy per molecule of an ideal gas is given by the formula $KE_{avg} = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant $(1.38 	imes 10^{-23} \, J/K)$ and $T$ is the temperature in Kelvin.Given $T = 25 + 273.15 = 298.15 \, K$.Substituting the values: $KE_{avg} = \frac{3}{2} 	imes (1.38 	imes 10^{-23} \, J/K) 	imes 298.15 \, K$.$KE_{avg} = 1.5 	imes 1.38 	imes 298.15 	imes 10^{-23} \, J$.$KE_{avg} \approx 6.17 	imes 10^{-21} \, J$.

The average kinetic energy per molecule of an ideal gas at $25\,^oC$ in $SI$ units is.....

Similar Questions

If the kinetic energy in $J$, of $CH_4$ (molar mass $= 16 \ g \ mol^{-1}$) at $T(K)$ is $X$, the kinetic energy in $J$, of $O_2$ (molar mass $= 32 \ g \ mol^{-1}$) at the same temperature is

Give two unfair assumptions of the Kinetic Molecular Theory of gases. Justify them.

At the same temperature and pressure,which of the following gases will have the highest kinetic energy $(K.E)$ per mole?

According to the kinetic molecular theory of gases,the total kinetic energy of a gas depends on......

The average kinetic energy of one molecule of an ideal gas at $27^{\circ} C$ and $1 \ atm$ pressure is

Vedclass Test Series

Exam Paper Generator

Online Exam Module