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(B) According to Graham's Law of Diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $r \propto \f

Vedclass · Accepted Answer

$2$

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(B) According to Graham's Law of Diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $r \propto \frac{1}{\sqrt{M}}$.Therefore,the ratio of the rate of diffusion of helium $(He)$ to methane $(CH_4)$ is given by:$\frac{r_{He}}{r_{CH_4}} = \sqrt{\frac{M_{CH_4}}{M_{He}}}$Given molar masses: $M_{He} = 4 \ g/mol$ and $M_{CH_4} = 16 \ g/mol$.Substituting the values:$\frac{r_{He}}{r_{CH_4}} = \sqrt{\frac{16}{4}} = \sqrt{4} = 2$.

Under standard conditions of temperature and pressure,what will be the ratio of the rate of diffusion of helium to methane?

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