If the energy of a photon is 14 , eV and it i | vedclass

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(B) The ionization energy of a hydrogen atom in its ground state is $13.6 \, eV$. When a photon with energy $E = 14 \, eV$ interacts with the hydrogen

Vedclass · Accepted Answer

The atom is ionized and the electron has a kinetic energy of $0.4 \, eV$.

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(B) The ionization energy of a hydrogen atom in its ground state is $13.6 \, eV$. When a photon with energy $E = 14 \, eV$ interacts with the hydrogen atom,it provides more energy than the ionization energy. The excess energy is converted into the kinetic energy of the ejected electron. Kinetic Energy $(K.E.)$ = $E_{photon} - E_{ionization} = 14 \, eV - 13.6 \, eV = 0.4 \, eV$. Therefore,the atom is ionized and the electron possesses a kinetic energy of $0.4 \, eV$.

If the energy of a photon is $14 \, eV$ and it interacts with a hydrogen atom,which of the following is correct?

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