An electron having quantum numbers $n = 4, l = 3, m = 0, s = -1/2$ is present in which orbital?

  • A
    $3s$
  • B
    $3p$
  • C
    $4d$
  • D
    $4f$

Explore More

Similar Questions

Which electronic configuration does not follow the $(n + l)$ rule?

The state of an electron in a $3d_{z^2}$ orbital is described by which quantum numbers?

Difficult
View Solution

In an atom, the order of increasing energy of electrons with quantum numbers $(i)$ $n=4, l=1$, (ii) $n=4, l=0$, (iii) $n=3, l=2$, and (iv) $n=3, l=1$ is:

The four quantum numbers for the valence shell electron or last electron of sodium $(Z = 11)$ are:

What is the electronic configuration of $Cu^{2+} (Z = 29)$ in its ground state?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo