When an electron transitions from n = 4 to n | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The Rydberg formula for the spectral lines of hydrogen is given by $\frac{1}{\lambda} = R_H 	imes Z^2 	imes (\frac{1}{n_1^2} - \frac{1}{n_2^2})$

Vedclass · Accepted Answer

Second line of Balmer series

Vedclass · Answer

(B) The Rydberg formula for the spectral lines of hydrogen is given by $\frac{1}{\lambda} = R_H 	imes Z^2 	imes (\frac{1}{n_1^2} - \frac{1}{n_2^2})$.For the Balmer series,the transition ends at $n_1 = 2$.The lines in the Balmer series are defined by transitions from $n_2 = 3, 4, 5, \dots$ to $n_1 = 2$.- The first line $(H_\alpha)$ corresponds to $n = 3 	o n = 2$.- The second line $(H_\beta)$ corresponds to $n = 4 	o n = 2$.Therefore,the transition from $n = 4$ to $n = 2$ represents the second line of the Balmer series.

When an electron transitions from $n = 4$ to $n = 2$,the emitted spectral line will be ........

Similar Questions

Which one of the following is considered as the main postulate of Bohr’s model of atom?

The energy required to excite an electron from the first orbit to the third orbit in a hydrogen atom is .......... $eV$.

Henry Moseley studied the characteristic $X$-ray spectra of elements. The graph which represents his observation correctly is: (Given $\nu =$ frequency of $X$-ray emitted; $Z =$ atomic number)

Who modified Bohr's theory by introducing elliptical orbits for electron path?

In which transition is minimum energy emitted?

Vedclass Test Series

Exam Paper Generator

Online Exam Module