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(B) The de Broglie wavelength $(\lambda)$ is related to kinetic energy $(K)$ by the formula: $\lambda = \frac{h}{\sqrt{2mK}}$.Since $\lambda \propto \

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Becomes half

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(B) The de Broglie wavelength $(\lambda)$ is related to kinetic energy $(K)$ by the formula: $\lambda = \frac{h}{\sqrt{2mK}}$.Since $\lambda \propto \frac{1}{\sqrt{K}}$,if the kinetic energy $K$ becomes $4K$,the new wavelength $\lambda'$ will be: $\lambda' = \frac{h}{\sqrt{2m(4K)}} = \frac{1}{2} 	imes \frac{h}{\sqrt{2mK}} = \frac{1}{2} \lambda$.Therefore,the wavelength becomes half of its original value.

If the kinetic energy of an electron is increased by $4$ times,what will be the change in its associated de Broglie wavelength?

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