The atomic number of the element (in ground s | vedclass

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Question

(A) The electronic configuration of the given elements in their ground state is as follows:$1.$ For atomic number $8$ $(O)$: $1s^2 2s^2 2p^4$. Number

Vedclass · Accepted Answer

$15$

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(A) The electronic configuration of the given elements in their ground state is as follows:$1.$ For atomic number $8$ $(O)$: $1s^2 2s^2 2p^4$. Number of unpaired $3p$ electrons = $0$.$2.$ For atomic number $10$ $(Ne)$: $1s^2 2s^2 2p^6$. Number of unpaired $3p$ electrons = $0$.$3.$ For atomic number $12$ $(Mg)$: $1s^2 2s^2 2p^6 3s^2$. Number of unpaired $3p$ electrons = $0$.$4.$ For atomic number $15$ $(P)$: $1s^2 2s^2 2p^6 3s^2 3p^3$. The $3p$ subshell has $3$ orbitals,each containing $1$ unpaired electron according to Hund's rule.Thus,the element with atomic number $15$ has the maximum number of unpaired $3p$ electrons ($3$ unpaired electrons).

The atomic number of the element (in ground state) having the maximum number of unpaired $3p$ electrons is:

Similar Questions

The $20^{th}$ electron of $Fe$ $(Z = 26)$ has which of the following sets of quantum numbers?

For the given quantum numbers,write the name of the subshell,the values of the magnetic quantum number $(m_l)$,and the number of orbitals:
$(i) \ n = 3, \ l = 2$
$(ii) \ n = 4, \ l = 3$
$(iii) \ n = 2, \ l = 0$
$(iv) \ n = 5, \ l = 1$

The two electrons in the $K$ shell will differ in which of the following quantum numbers?

The electronic configurations of four elements are given in brackets: $L\,(1s^2, 2s^2 2p^1)$; $M\,(1s^2, 2s^2 2p^5)$; $Q\,(1s^2, 2s^2 2p^6, 3s^1)$; $R\,(1s^2, 2s^2 2p^2)$. Which element would most readily form a diatomic molecule?

The number of unpaired electrons in $Ni$ (atomic number $= 28$) is:

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