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(C) The atomic number of chlorine $(Cl)$ is $17$.The electronic configuration of $Cl$ is $1s^2 2s^2 2p^6 3s^2 3p^5$.The unpaired electron is present i

Vedclass · Accepted Answer

$n = 3, l = 1, m = 1, s = 1/2$

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(C) The atomic number of chlorine $(Cl)$ is $17$.The electronic configuration of $Cl$ is $1s^2 2s^2 2p^6 3s^2 3p^5$.The unpaired electron is present in the $3p$ orbital.For the $3p$ orbital,the principal quantum number $n = 3$ and the azimuthal quantum number $l = 1$.The magnetic quantum number $m$ can be $-1, 0, +1$,and the spin quantum number $s$ can be $\pm 1/2$.Comparing this with the given options,option $C$ $(n = 3, l = 1, m = 1, s = 1/2)$ represents a valid set of quantum numbers for an electron in the $3p$ subshell.

Which set of quantum numbers is correct for the unpaired electron of a chlorine atom?

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Assertion : An orbital designated by $n = 3, l = 1$ has double dumb-bell shape.
Reason : It belongs to $p-$subshell.

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