In the atom _{13}Al^{27},the number of proton | vedclass

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(A) For the atom $_{13}Al^{27}$:$1$. The atomic number $(Z)$ is $13$,which represents the number of protons $(a = 13)$.$2$. In a neutral atom,the numb

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$14 : 13 : 13$

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(A) For the atom $_{13}Al^{27}$:$1$. The atomic number $(Z)$ is $13$,which represents the number of protons $(a = 13)$.$2$. In a neutral atom,the number of electrons $(b)$ is equal to the number of protons,so $b = 13$.$3$. The mass number $(A)$ is $27$. The number of neutrons $(c)$ is calculated as $A - Z = 27 - 13 = 14$.$4$. The required ratio $(c : b : a)$ is $14 : 13 : 13$.

In the atom $_{13}Al^{27}$,the number of protons $(a)$,electrons $(b)$,and neutrons $(c)$ are present. Determine the ratio in the order $(c : b : a)$.

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