The energy of one mole of photons of radiatio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The energy of one photon is given by $E = h
u$. Given: $h = 6.626 	imes 10^{-34} \, J \cdot s$ and $
u = 5 	imes 10^{10} \, s^{-1}$. Energy of

Vedclass · Accepted Answer

$19.93$

Vedclass · Answer

(B) The energy of one photon is given by $E = h
u$. Given: $h = 6.626 	imes 10^{-34} \, J \cdot s$ and $
u = 5 	imes 10^{10} \, s^{-1}$. Energy of one photon = $(6.626 	imes 10^{-34} \, J \cdot s) 	imes (5 	imes 10^{10} \, s^{-1}) = 3.313 	imes 10^{-23} \, J$. Energy of one mole of photons = (Energy of one photon) $	imes$ (Avogadro constant $N_A$). Energy = $(3.313 	imes 10^{-23} \, J) 	imes (6.022 	imes 10^{23} \, mol^{-1}) \approx 19.95 \, J \, mol^{-1}$. Rounding to the nearest provided option,the answer is $19.93 \, J$.

The energy of one mole of photons of radiation whose frequency is $5 \times 10^{10} \, s^{-1}$ is .......... $J$.

Similar Questions

Which of the following radiations has the highest energy?

Calculate the energy of one mole of photons of radiation whose frequency is $5 \times 10^{14} \ Hz$.

The energy of one mole of photons of radiation of wavelength $300 \ nm$ is ...... $kJ \ mol^{-1}$. (Given: $h = 6.63 \times 10^{-34} \ J \ s, N_A = 6.02 \times 10^{23} \ mol^{-1}, c = 3 \times 10^8 \ m \ s^{-1}$)

Calculate the wavelength,frequency and wave number of a light wave whose period is $2.0 \times 10^{-10} \,s$.

Work functions of four metals $M_1, M_2, M_3$ and $M_4$ are $4.8, 4.3, 4.75$ and $3.75 \ eV$ respectively. The metals which do not show photoelectric effect when light of wavelength $310 \ nm$ falls on the metals are

Vedclass Test Series

Exam Paper Generator

Online Exam Module