Calculate the wavelength of an electron if it | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: Mass $m = 9.1 	imes 10^{-31} \, kg$,Velocity $v = \frac{1}{10} 	imes c = \frac{1}{10} 	imes 3 	imes 10^8 \, m/s = 3 	imes 10^7 \, m/s$

Vedclass · Accepted Answer

$2.426 	imes 10^{-11} \, m$

Vedclass · Answer

(C) Given: Mass $m = 9.1 	imes 10^{-31} \, kg$,Velocity $v = \frac{1}{10} 	imes c = \frac{1}{10} 	imes 3 	imes 10^8 \, m/s = 3 	imes 10^7 \, m/s$,Planck's constant $h = 6.626 	imes 10^{-34} \, J \cdot s$.Using the de Broglie wavelength formula: $\lambda = \frac{h}{mv}$.$\lambda = \frac{6.626 	imes 10^{-34} \, J \cdot s}{(9.1 	imes 10^{-31} \, kg) 	imes (3 	imes 10^7 \, m/s)}$.$\lambda = \frac{6.626 	imes 10^{-34}}{27.3 	imes 10^{-24}} \, m$.$\lambda \approx 0.2427 	imes 10^{-10} \, m = 2.427 	imes 10^{-11} \, m$.

Calculate the wavelength of an electron if its mass is $9.1 \times 10^{-31} \, kg$,its velocity is $1/10$ of the speed of light,and the value of Planck's constant $h$ is $6.626 \times 10^{-34} \, J \cdot s$.

Similar Questions

If the de Broglie wavelength of the electron in the $n^{th}$ Bohr orbit in a hydrogenic atom is equal to $1.5 \, \pi \, a_0$ ($a_0$ is Bohr radius),then the value of $n/Z$ is:

If the kinetic energy of an electron of mass $9.0 \times 10^{-31} \ kg$ is $2.0 \times 10^{-25} \ J$,the wavelength of the electron in $nm$ is approximately (in $.3$)

The kinetic energy of a proton wave is $500 \ eV$. Calculate its de Broglie wavelength. (Mass of proton $= 1.67 \times 10^{-27} \ kg$)

The de Broglie wavelength associated with a ball of mass $1 \, kg$ having kinetic energy $0.5 \, J$ is

Which one of the following explains light both as a stream of particles and as wave motion?

Vedclass Test Series

Exam Paper Generator

Online Exam Module